A water balloon is tossed into the air with an upward velocity of 25 ft/s. Its height h(t) in ft after t seconds is given by the function h(t) = − 16t^2 + 25t + 3.

After how many seconds will the balloon hit the ground?

What will the height be at t = 1 second?

Question

A water balloon is tossed into the air with an upward velocity of 25 ft/s. Its height h(t) in ft after t seconds is given by the function h(t) = − 16t^2 + 25t + 3. 

After how many seconds will the balloon hit the ground? 

What will the height be at t = 1 second?

alekos · Answer

so you need to find t when h(t) = 0

alekos · Answer

so we have   -16t^2 +25t + 3  = 0

now solve for t

anonymous · Answer

hang on its gonna take me a second

anonymous · Answer

253/25

alekos · Answer

no, that's not it

alekos · Answer

try again

alekos · Answer

the second part is easy, just find h(1)

er.mohd.amir · Answer

-16t^2+25+3=0 is a quadratic eq. so use formula for factor it 
if eq is ax^2+bx+c=0 thhen solution are given x={-b+sqrt (b*b-4ac) }/ 2a and x={-b-sqtr (b*b-4ac)} / 2a