Simplify 4 over -2 - 2i -1 - i -2 - i -1 + i -2 + i
\[\huge\rm \frac{ 4 }{ -2-2i }\] multiply top and bottom of the fraction by the conjugate of the denominator
what does that mean?
do you know what conjugate is ?
no
conjugate of a +bi is `a-bi` change the sign of imaginary term
so what's the conjugate of `-2-2i` ?
-2+2i?
right now multiply numerator and denominator by `-2+2i`\[\large\rm \frac{ 4 }{ -2-2i }*\frac{-2+2i}{-2+2i}\]
familiar with the distributive property ?
lol dude basically you flip the middle sign of the denometer and multiply its by the numerator
multiply by both *denominator and numerator *
I still dont understand.
it's like rationalize the denominator when we have to move radical sign from bottom to the top
to move the imaginary term from the denominator we should multiply top and bottom by the `conjugate ` of the denominator (which is -2-2i)
conjugate of -2-2i is `-2+2i` right so now multiply both top and bottom by -2+2i make sense ?
so... 4 and -2+2i times -2+2i?
right \[\large\rm \frac{ 4 }{ -2-2i }*\frac{-2+2i}{-2+2i}\] which can be written as \[\large\rm \frac{ 4(-2+2i) }{ (-2-2i)(-2+2i) }\]
then what?
now apply distributive property 4(-2+2i) and foil (-2-2i)(-2+2i)
so -8+8i over 4 - 2i ?
distributive property \[\rm a(b+c)=a*b+a*c=ab+ac\]
-8+8i is correct but how did you get 4-2i ?
remember \[\large\rm i= \sqrt{-1} ~~~and ~~~~~~~~~i^2= -1\]
I don't understand the bottom part I tried foil but I don't get it and I need to finish this test
how did you foil it. show your work . i'll try to find out the mistake
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