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Mathematics 22 Online
OpenStudy (calculusxy):

MEDAL!

OpenStudy (calculusxy):

OpenStudy (calculusxy):

@Nnesha

OpenStudy (anonymous):

This is actually just simple division :) Speed in this scenario is measured by km/h "kilometers per hour" So if she initially drove 500 km over the course of 5 hours, then that means that her speed was 500/5=10 km/hr! Do the same thing for her return time! Also note that you will have to convert the 20 minutes to an hour and add to the 4.

OpenStudy (calculusxy):

Should I do: \[\large \frac{500}{4 \frac{1}{3}}\]

OpenStudy (anonymous):

Yep!! Assuming that you are considering that a mixed fraction and not mistakenly solving with 4/3 :)

OpenStudy (calculusxy):

So it would be something like: \[\large \frac{ 1500 }{ 13 }\] and then i would further divide it?

OpenStudy (anonymous):

Yep! :)

OpenStudy (calculusxy):

It would be around 115.4 km/h.

OpenStudy (anonymous):

That's what I got :) And this makes sense because if she returned faster than she got there, then she would have to travel faster than before!

OpenStudy (calculusxy):

But the answer key says that it's A.

OpenStudy (anonymous):

Probably a typo! They unit for speed is distance/time. On the way there, 500/5=100km/hr On the way back, 500/(13/3)=115.38hm/hr ~ 115.5

OpenStudy (calculusxy):

Maybe. Anyway, thank you!

OpenStudy (anonymous):

You're welcome :)

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