Given the function f(x) = log3(x + 4), find the value of f−1(3).
You want to find, \(\large\color{black}{ \displaystyle f^{-1}\left(3\right) }\)
\(\large\color{black}{ \displaystyle y=\log_3(x+4)}\)
\(\bf [1]\) swipe around x and y. \(\bf [2]\) isolate the y. \(\bf [{~}lastly{~}]\) plug in 3 for x.
Or, you can simply plug in 3 for y, and solve for x.
\(\large\color{red}{3}=\log_3(x+4)\)
so I swipe x and y in the first equation?
Yes, you can swipe x and y in the first equation then solve for x, and then plug in 3 for x.
Or, alternatively, you can plug in 3 for y, and solve for x.
Either way you get the answer, except that way 1 is standard and way 2 is quicker.
x=23 correct?
I don't really know.... can you please tell me, how did you get this result?
substituted 3 for y
yes, and then solve for x. 23 is correct
So you will get that: \(\large\color{black}{ \displaystyle f^{-1}(3)=23 }\)
Thank you for your help!!
yw
Join our real-time social learning platform and learn together with your friends!