Mathematics
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OpenStudy (anonymous):
i need help please!!!!
solve using factoring,complete the square,square root property or quadratic formula.
A) x^2-4x+9=0
B) 1/5x-1/4x +1/3x =-17/60
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OpenStudy (anonymous):
the firrst one will have complex zeros (not real ones) is that ok?
OpenStudy (anonymous):
can you explain to me please
OpenStudy (anonymous):
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OpenStudy (anonymous):
is it \[x^2-4x+9=0\]?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
subtract 9 from both sides
get \[x^2-4x=-9\] not plus 9
OpenStudy (anonymous):
omg, yes!! you are right! my mistake
OpenStudy (anonymous):
then half of 4 is 2 and 2 squared is 4 so go right to
\[(x-2)^2=-9+4\] or \[(x-2)^2=-5\]
OpenStudy (anonymous):
yes! thank you, is that the final answer for part A?
OpenStudy (anonymous):
no
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OpenStudy (anonymous):
are you allowed complex numbers?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
\[(x-2)^2=-5\\
x-2=\pm\sqrt{5}i\\
x=2\pm\sqrt{5}i\]
last line is the "final answer "
OpenStudy (anonymous):
does the i remain under the square root or does it come out?
OpenStudy (anonymous):
the \(i\) is the outside the square root
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OpenStudy (anonymous):
\[\sqrt{-5}=\sqrt5\sqrt{-1}=\sqrt5i\]
OpenStudy (anonymous):
oh okay
OpenStudy (anonymous):
got it, thanks so much
OpenStudy (anonymous):
could you also help me with B?
OpenStudy (anonymous):
sure
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OpenStudy (anonymous):
is it \[\frac{1}{5}x-\frac{1}{4}x+\frac{1}{3}x=-\frac{17}{60}\]?
OpenStudy (anonymous):
the x's are with the denominators, i dont know if that makes a difference
OpenStudy (anonymous):
yes is certainly does!
OpenStudy (anonymous):
\[\frac{1}{5x}-\frac{1}{4x}+\frac{1}{3x}=-\frac{17}{60}\]like that?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
multiply both sides by \(60x\)
OpenStudy (anonymous):
** also, the negative on the right of the equal sign was in the numerator**sorry
OpenStudy (anonymous):
that makes no difference
OpenStudy (anonymous):
\[12x-15x+10x=-17x\]
OpenStudy (anonymous):
each term is multiplied by 60x?
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OpenStudy (anonymous):
yes, but there is no solution
OpenStudy (anonymous):
oh wait hold on
OpenStudy (anonymous):
i made a mistake
multiply both sides by \(60x\) you get \[12-15+10=-17x\]you can solve that for \(x\)
OpenStudy (anonymous):
you get \[-7=-17x\] and so \[x=\frac{7}{17}\]
OpenStudy (anonymous):
i got that x should equal -1 :S
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OpenStudy (anonymous):
1/3x * 60x is 20
OpenStudy (anonymous):
oops
OpenStudy (anonymous):
i mean oops on my part
OpenStudy (anonymous):
its okay :)
thank you!! you were such a huge help
OpenStudy (anonymous):
\[12-15+20=17\] so you are right and i am wrong
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OpenStudy (anonymous):
yw