Question

(y-c)^2-tc sin^2 (l)-t/2sin^2(l){-y+sqrt(-3y^2+4yc)}=0 solve it

Answer 1

solve for y

Answer 2

do you mind drawing? it's easier for me to see the real problem

Answer 3

what do u mean by drawing graph???

Answer 4

i have no graph...i want guidence to solve it

Answer 5

I think she is talking about using the draw tool because the equation you have written is hard to read.

Answer 6

let me try to make it out though

Answer 7

\[(y-c)^2-tc \sin^2 (l)-\frac{t}{2} \sin^2(l){-y+\sqrt{-3y^2+4yc}}=0\]


is that right?

Answer 8

-y+sqrt(-3y^2+4yc) is multiplying with t/csin^2(l)

Answer 9

\[(y-c)^2-tcsin^2(l)-\frac{t(-y+\sqrt{-3y^2+4yc})}{2\sin^2(l)}=0\]is it like this?

Answer 10

sin^2(l)is in numerator in last term

Answer 11

i want to solve it for the value of y

Answer 12

plz help

Answer 13

i also want to ask how u write an equation like this

Answer 14

help plz

Answer 15

:)

Answer 16

can u write the equation using the equation tool?

Answer 17

from where i can get equ tool???

Answer 18

http://prntscr.com/8y31jz

Answer 19

@rosy

Answer 20

ok ok thank u:)