Question

give me some Graphing Quadratic Functions,

Answer 1

@IrishBoy123

Answer 2

you can play with the sliders
https://www.desmos.com/calculator/p69hhmoyxe

Answer 3

slider b is fun 🌝

Answer 4

i want to practice graphing

Answer 5

graph this-\[4x^2-2x+2=0\]
then graph this-\[2x^2-x+1=0\]

Answer 6

graph without using calculator

Answer 7

so i might not be able to post the answer

Answer 8

ok jst try it
post a rough sketch :)

Answer 9

ok, i will be back after 30 minutes, i have to do my chem hw ok?

Answer 10

20 minutes not 30

Answer 11

ok?

Answer 12

okay B)

Answer 13

stay here ok

Answer 14

sry i have to go to arctic to hunt penguins so i won't be here ):

Answer 15

really that kind off joke

Answer 16

do you know the intersection thing in quad

Answer 17

plot the graphs there are more jokes to come :)

Answer 18

wym?

Answer 19

intersection of quadratics with lines and with other quadratics

Answer 20

for example

Answer 21

sketch the graph of f(x) = x +2 on the grid
sketch the grapgh of f(x) = x^2
find the points of intersections algebrically

Answer 22

like that

Answer 23

oh ok yes :)

Answer 24

ask me stuff like that

Answer 25

u want me to ask u ques based on quadratic eqs?

Answer 26

no, on solving using perfect squares, i am week in perfect squares i need help in that

Answer 27

ok solve this quad eq using the perfect square technique-
\[4x^2+9x+5=0\]

Answer 28

but remember i am just in 10th

Answer 29

ik :)

Answer 30

how do you solve it

Answer 31

4x^2 + 9x + = 5 then?

Answer 32

will you reply till tmrw

Answer 33

ok jst follow these simple steps-
if u have any quad eq like this-\[ax^2+bx+c=0\]

Answer 34

just divide all over by a u get this-\[x^2 +\frac{ bx }{ a }+\frac{ c }{ a }=0\]

Answer 35

tell ok if ur following the steps
ok?

Answer 36

we did not learn that yet

Answer 37

i didn't do anything special i jst divided

Answer 38

we do this 4x^2 + 9x + = 5
than we find a number that multiply to 9 and adds to 5

Answer 39

this is not the perfect square method this is the factorization method

which method do u wanna learn

Answer 40

square root method

Answer 41

u mean the perfect square method right? :)

Answer 42

yeah

Answer 43

lets just do with x^2 + 2x + 4 = 0 too make it easy

Answer 44

ok

Answer 45

now we have to make a perfect square

Answer 46

the perfect square should be of this form-\[(x+p)^2=q\]

Answer 47

ok, how

Answer 48

my bad completing the square method, sorry

Answer 49

1st u take the constant term(the term without x) onthe other side

2nd u should focus on the coefficient of x^2 term

if the coefficient is not 1 and is some other number say n
then u just divide all over by n
ok?

in this case the coefficient is 1
so we don't have to worry

3rd u focus upon the term which is having x in it
lets say the term is kx
u multiply divide this term by 2
then u get this- 2(k/2)(x)

we lets apply these steps in our ques
\[x^2+2x+4=0\]
\[x^2+2x=-4\]

2nd coefficient of x=1
so no need to divide and all

3rd we see the x term it is 2x divide and multiply it by 2 u get this-
\[x^2+2(\frac{ 2 }{ 2 })(x)=-4\]

now we observe it carefully
we see that this thing is like
\[x^2 + \left( \frac{ 2 }{ 2 }\right)^2+2\left( \frac{ 2 }{ 2 } \right)(x)=-4\]

the only problem is that it doesn't have (2/2)^2 in it

so we add (2/2)^2 on both sides

we get this-
\[x^2 + 2\left( \frac{ 2 }{ 2 } \right)(x)+\left( \frac{ 2 }{ 2 } \right)^2=-4+\left( \frac{ 2 }{ 2 } \right)^2\]\[\left( x+\frac{ 2 }{ 2 } \right)^2=-4+1\]\[(x+1)^2=-3\]

this equation has no real roots cause the square of any number can't be negative

Answer 50

ok, since I understand this, lets do graph using vertex form and factored form, ok

Answer 51

ok?

Answer 52

:) ok

Answer 53

what do u knw about these forms

Answer 54

15 minute study break

Answer 55

x'D ok

Answer 56

@imqwerty

Answer 57

@imqwerty