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Mathematics 14 Online
OpenStudy (anonymous):

simplifying the trig expression

OpenStudy (anonymous):

OpenStudy (anonymous):

would it simplify to = -1 (cosh\[=-1/(\cos \emptyset-1)^2\]

ganeshie8 (ganeshie8):

Yes\[\dfrac{\cos\theta-1}{(1-\cos\theta)^3} = \dfrac{-1(1-\cos\theta)}{(1-\cos\theta)^3} = \dfrac{-1}{(1-\cos\theta)^2}\]

OpenStudy (anonymous):

because the solution gives this

OpenStudy (anonymous):

shouldn't it be : −1/(1−cosθ)^2 < 0

ganeshie8 (ganeshie8):

You're absolutely correct! let me double check it with wolfram

OpenStudy (anonymous):

thanks

ganeshie8 (ganeshie8):

Yes, you're right. There is no way \(\dfrac{-1}{(1-\cos\theta)^2}\) simplifies to \(-(1-\cos\theta)^2\).

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