Which of the following is a quadratic equation that has the roots x = 2 and x = −7? x2 − 5x − 14 = 0 x2 − 5x = −14 x2 + 5x = 14 x2 + 5x = −14
I believe that this is C but would like some clarification. and yeah lunch seems great right now lol @Majesty69
@Maddy1251
i accidentally pressed the wrong name lol
Lol it happens! Do you know how to find roots?
mmm based off of context clues I could figure it out but not off the top of my head, no.
Roots are what makes a function equal 0, when we plug in certain 'x' terms, we get the equation to equal zero. Factoring is a great way to help, however in this case if you do not want to factor, you can plug in your given roots to find what yields 0.
oh also i dont believe its c i think B my bad. I just realized theers a negative but you can still explain. I want to know for sure.
I like all my equations to be set to zero when finding roots.
x2 − 5x − 14 = 0 Good. x2 − 5x = −14 --> x^2-5x+14=0 x2 + 5x = 14 --> x^2+5x-14=0 x2 + 5x = −14 ----> x^2+5x+14=0.
So, now we can just plug in x=2 and x=-7.
wow really ... I was considering that but im not sure if the zero plays a role, and if i does play a role i dont know how it does.
I will explain why we have zeros first, then proceed.
When we factor an equation like (x+7)(x-5)=0, we want to know how to get (0)(0)=0 In this case x=-7 for the first part, and x=5 for the second. These are known as the roots.
That's just an example, not sure if those roots truly work, but its a vision to see what roots really are and how they work.
Then when you would expand the problem, both of those roots would produce the polynomial to equal zero.
I have to eat real quick, but the answer is C. Try figuring it out to see why it is C.
a hah so far i understand. and ok will do.
I am back.
wow So i was right in the first place when I said C but then I second guess myself because of the negative. However I dont wish to guess that, think you can perhaps explain what happened to the negative.
does it have soemthing to do with cancelling out the numbers?
when I distribute?
No, and well you don't have to distribute. Not yet.
Remember how I set them to zero?
yeah
We have roots x=2 and x=-7
(x+2)(x-7)= ? Distribute that
ok give me a minute
x2 − 5x − 14 = 0 Good. x2 − 5x = −14 --> x^2-5x+14=0 x2 + 5x = 14 --> x^2+5x-14=0 x2 + 5x = −14 ----> x^2+5x+14=0. See which of these equals (x+2)(x-7) Take your time
the two x's make x^2 + x7 - 2x + 14? or was it a minus 14?
0.o a 5? where did that come from?
I will distribute for you.
|dw:1446489014822:dw|
Join our real-time social learning platform and learn together with your friends!