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if f(x)=(x^2-16)/(x+4) is continuous at x = -4, find f(-4).
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\[f(-4)=(-4^{2}-16)/(-4+4)\]
I got 0 but my answer choices aare 4,-4,8,-8
This doesn't make sense. It would be undefined anyways because 0 cannot be the denominator
Wait, we need to simplify it first.
ok thanks ill just ask my teacher about it
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\[(x^2-16)=(x+4)(x-4)\] So then we are left with \[(x-4)\]\[(-4)-4\]\[-8\]:)
Hopefully that helps lol
ohhh ok thanks so much
Thank you @haleyelizabeth2017
No problem :)
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