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OpenStudy (anonymous):
OpenStudy (anonymous):
I think you have to find the LCM of 6 and 9
OpenStudy (maddy1251):
I can help.
OpenStudy (anonymous):
go ahead.
OpenStudy (maddy1251):
Is this Alg?
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OpenStudy (anonymous):
probs & stats
OpenStudy (maddy1251):
I thought so. This is a permutation or combinations problem.
OpenStudy (maddy1251):
Permutations are for lists, where order mattes. Combinations are for groups, where order doesn't matter. What do you think we will use?
OpenStudy (anonymous):
combinations
OpenStudy (maddy1251):
Yup, because his isn't like selecting the order of who will be president, VP, etc.. I mean I am sure it matters to the girls but that's personal reasons. ;-) Do you know the formula for combinations?
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OpenStudy (maddy1251):
\[\frac{ n! }{ r!(n-r)! }\]
OpenStudy (maddy1251):
r objects from the set of n objects.
OpenStudy (maddy1251):
\[\frac{ 9! }{ 6!(9-6)! }\]
OpenStudy (maddy1251):
\[\frac{ 9! }{ 6!(3)! }\]
OpenStudy (maddy1251):
That should yield 84.
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OpenStudy (maddy1251):
Unless my calculator messed up.
OpenStudy (anonymous):
how about this one?
OpenStudy (maddy1251):
C, possibly.
OpenStudy (maddy1251):
I added them together to find total for sprint. then Divided by number of women in sprinting
OpenStudy (anonymous):
did you get the first one ?
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OpenStudy (anonymous):
oh yes you did i see it
OpenStudy (amistre64):
if we put all the women in a room, what is the probability that a randomly chosen female ... does sprints?
OpenStudy (amistre64):
as opposed to: what is the probability that out of all the sprinters, a randomly chosen sprinter is a female ...
OpenStudy (anonymous):
12 female sprints.
OpenStudy (anonymous):
could it be out of 1?
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