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Mathematics 13 Online
OpenStudy (anonymous):

multiple choice answers.

OpenStudy (anonymous):

OpenStudy (anonymous):

I think you have to find the LCM of 6 and 9

OpenStudy (maddy1251):

I can help.

OpenStudy (anonymous):

go ahead.

OpenStudy (maddy1251):

Is this Alg?

OpenStudy (anonymous):

probs & stats

OpenStudy (maddy1251):

I thought so. This is a permutation or combinations problem.

OpenStudy (maddy1251):

Permutations are for lists, where order mattes. Combinations are for groups, where order doesn't matter. What do you think we will use?

OpenStudy (anonymous):

combinations

OpenStudy (maddy1251):

Yup, because his isn't like selecting the order of who will be president, VP, etc.. I mean I am sure it matters to the girls but that's personal reasons. ;-) Do you know the formula for combinations?

OpenStudy (maddy1251):

\[\frac{ n! }{ r!(n-r)! }\]

OpenStudy (maddy1251):

r objects from the set of n objects.

OpenStudy (maddy1251):

\[\frac{ 9! }{ 6!(9-6)! }\]

OpenStudy (maddy1251):

\[\frac{ 9! }{ 6!(3)! }\]

OpenStudy (maddy1251):

That should yield 84.

OpenStudy (maddy1251):

Unless my calculator messed up.

OpenStudy (anonymous):

how about this one?

OpenStudy (maddy1251):

C, possibly.

OpenStudy (maddy1251):

I added them together to find total for sprint. then Divided by number of women in sprinting

OpenStudy (anonymous):

did you get the first one ?

OpenStudy (anonymous):

oh yes you did i see it

OpenStudy (amistre64):

if we put all the women in a room, what is the probability that a randomly chosen female ... does sprints?

OpenStudy (amistre64):

as opposed to: what is the probability that out of all the sprinters, a randomly chosen sprinter is a female ...

OpenStudy (anonymous):

12 female sprints.

OpenStudy (anonymous):

could it be out of 1?

OpenStudy (anonymous):

@amistre64

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