Question

My friend got 1/15 whereas I got 15/16 for the following series:

Answer 1

\[\sum_{n=1}^{\infty} \frac{ 1^{n} }{ (-15)^{n-1} }\]

Answer 2

it can't really be \(1^n\) can it?

Answer 3

It unfortunately is :/

Answer 4

lol
ok you are right your friend is wrong

Answer 5

Just a guess? :P

Answer 6

no not a guess, you can do it in your head

Answer 7

You're obviously way more educated than I am then

Answer 8

whats is \(1-(-\frac{1}{15})\)?

Answer 9

aka \[1+\frac{1}{15}\]?

Answer 10

16/15?

Answer 11

yes of course
and the reciprocal of \(\frac{16}{15}\) is?

Answer 12

15/16?

Answer 13

no not 15/16? but rather 15/16 !!!
how hard was that?

Answer 14

Fair enough! I guess I'm just so used to the teacher saying to do questions a certain way that I didn't think about that, thanks!

Answer 15

i am not that educated, this is easy is all
for example \[\sum\left(\frac{2}{3}\right)^n\] \[1-\frac{2}{3}=\frac{1}{3}\] the reciprocal of \(\frac{1}{3}\) is \(3\) finished
math teaches like to make things harder than they actually are