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A population grows exponentially according to the differential equation dP, dt equals k times P, where P is the population, t is time, and k is a positive constant. If P(0) = A, what is the time for the population to triple its initial value?
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set \[e^{kt}=3\] solve for \(t\)
hope it is clear that the A is not important when it triples, it will be 3A and the first step in solving \[3A=Ae^{kt}\] is to divide both sides by \(A\)
\[\ln3/k\]
yes
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So it's B?
Yessir, I just tried my hand at it and that is indeed what I got
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