Find the absolute value of the resulting error if the value of is estimated with 3 trapezoids of equal width.
@jim_thompson5910
were you able to calculate the trapezoidal area? or the exact area?
No, how would I do that?
are you familiar with this rule? \[\Large \int x^n dx = \frac{x^{n+1}}{n+1} + C\]
Yes
If you integrate the whole thing it becomes (1/4)x^(4) |0 to 3, which is 81/4 by trapezoidal rule to estimate, you just add up the area under the curve in trapeziums, in this case, 3 intervals are, between 0 to 1, 1 to 2, and 2 to 3. so (0+1)/2 + (1+2^3)/2 + (2^3+3^3)/2 gives you 90/4, the error is therefore 9/4 and that's 2.25
Can you confirm @jim_thompson5910 ? His explanation definitely matched my thoughts here
yes @Kenshin is correct
Thank you @Kenshin and @jim_thompson5910
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