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derivative of sec 5x
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that's the same as asking for the derivative of cos^-1(5x) apply chain rule
@Kenshin be careful. That notation is inverse cosine and not secant
could it also be sec5xtan5x using the derivative of sec x being secxtanx?
you're very close
you have to use the chain rule
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you're right jim_thompson5910, i should have written (cos(5x))^-1
oh so multiply by 5 making it 5sec5xtan5x?
yep, if \(\Large y = \sec(5x)\) then \(\Large \frac{dy}{dx} = 5\sec(5x)\tan(5x)\)
okay thank you!
no problem
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