Question

thanks:)

Answer 1

The general form for a point slope equation is y=mx+b, where m is the slope and b is a constant (and the y-intercept).

The question gives you values for x, y, and m. Plug these in to solve for b. The equation for the line would then be y=mx+b, but with m and b replaced with the specific values you have here!

Answer 2

The point-slope form of a line with slope m and passing through a given point is the following:

y - y1 = m*(x - x1) where (x1, y1) is the point through which the line passes and m is the slope of the line.

http://www.purplemath.com/modules/strtlneq2.htm

Answer 3

(-1, 1) is the point P and -1 is the slope in this problem

y - y1 = m*(x - x1)

y - 1 = -1* (x - (-1) )

y - 1 = -1 ( x + 1)

is the equation of the line in point-slope form

>>write an point slope equation for line

Answer 4

In y = mx +b form, that becomes y = -x + 0.

However, the instructions indicated that the equation is to be left in point-slope form.

Answer 5

i think your right tho:)

Answer 6

Several days ago, I helped an Asker with a similar problem. There were options, all of the form akin to this: y - 1 = -1 ( x + 1)