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integral of trig function
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please try to use this identity: \[\Large 2\left( {1 - \cos \theta } \right) = 4{\left( {\sin \left( {\theta /2} \right)} \right)^2}\]
Nice use of the cos2θ identity
Another approach: \[\sqrt{2(1-\cos\theta)}=\frac{\sqrt2\sin\theta}{\sqrt{1+\cos\theta}}\]then simply substitute \(x=1+\cos\theta\).
no word from @swift?
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