Question

Fun problem about balancing penguins

Figure shows a mobile of toy penguins hanging from a ceiling. Each crossbar is horizontal, has negligible mass, and extends three times as far to the right of the wire supporting it as to the left. Penguin 1 has mass m1 = 48 kg. What are the masses of (a) penguin 2, (b) penguin 3, and (c) penguin 4?

Answer 1

Penguin 2(A) weighs 24 Kilograms, Penguin 3(B) weighs 12 Kilograms, and Penguin 4(C) weighs 12 kilograms.

Answer 2

While A would cut the first penguin's mass in half, it also must cut in half once again for the other two penguins to balance.

Answer 3

Haha nope. Your method may work if the wires supporting the crossbars are at middle I guess..

Answer 4

Oh, I can't believe I forgot about that!

Answer 5

A is 8 kilograms, and B is 4. But what is C?

Answer 6

Nice try. But still nope...

Answer 7

Care to tell me how to complete this?

Answer 8

what must the weight be on right hand side for perfect balance ?

Answer 9

OH 144 Kg!

Answer 10

i did it by finding relationship between mass using moment of inertia

i got m_{2}=12Kg m_{3}=3kg m_{4}=2kg

Answer 11

think again,
is it easy to open the door by pulling "far from pivot" or "near to pivot" ?

Answer 12

looks @imqwerty has it !
\(m_2=12\) and \(m_3=3\) are correct, but \(m_4\) is wrong

Answer 13

wait a sec

Answer 14

m_{4}=1kg !

Answer 15

Yep! could you also explain your method :)

Answer 16

umm