Question

3^n = 1/81 What value of "n" solves the equation?

Answer 1

k

Answer 2

hints:
laws of exponents: \(a^{-n}=\frac{1}{a^n}\)
this means the negation of the exponent changes the expression to its reciprocal.

Answer 3

Okay then what @mathmate

Answer 4

@Jnate621
Do you know how to solve for n in \(3^n=81\)

Answer 5

thats basically it. like 3^-1 would be 1/3 so 3^-2 would be 1/9 3^-3 would be 1/27. Once you think about it for a minute. its quite easy

Answer 6

The definition of exponents is"
\(a^n = a\times a\times....\times a\) n times.
So \(3^n = 3\times 3\times....\times 3\) n times. Can you find n?

Answer 7

if you have a negative exponent just make it a fraction. Im not quite sure how to explain it but its called law of exponents like math mate showed

Answer 8

So is N three? Im still confused.

Answer 9

@mathmate

Answer 10

is n was three 3^3 would be nine. However -3 is more on the right direction because 3^-3 would b 1/27. ill give you the hint your answer is negative

Answer 11

Check if n=3 by calculating 3^3=3*3*3

Answer 12

By the way, IF n=-3, 3^(-3) = 1/(3*3*3)

Answer 13

-4?

Answer 14

check your answer. what is 3^-4?

Answer 15

it would basically look like 1/3^4

Answer 16

1/81?

Answer 17

@mathmate

Answer 18

If you say \(3^{-4} = 1/81\), what is the correct answer for n?

Answer 19

Idk I wanna say its either -4 or 4. I did 3*3*3*3 and got 81.

Answer 20

The question says:
\(3^n = 1/81\) What value of "n" solves the equation?
and you say:
\(3^{-4} = 1/81\)
So what do you think is the answer for n?