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How much negative charge has been removed from a positively charged electroscope if it has a charge of 7.5x10 -11 C?
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faraday's constant links the amount of charge to a \(mole\) of electrons: \[1F = \frac{96,500 C}{1mol e^{-1}}\]since you know what \(fraction\) of charge moved, you can use the constant to convert to \(moles\) of electrons, and then to a \(number \) of electrons
it's 7.5x10^-11 ..bcz if you want to make a positive ion with charge 1 then you have remove one electron means negative charge .and same for the given situation .As given that it has a positive charge 7.5x10^-11 which means we have removed 7.5x10-11 negative charge from electroscope to make that positive charg
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