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Mathematics 11 Online
OpenStudy (anonymous):

For which values of the variable are the following statements true? Can someone show me how? I want to check my answers when I finish the work.

OpenStudy (anonymous):

OpenStudy (ghostgate):

Well, I'm not sure if this is right, but the first step would probably be to take the 'sqrt' variable, for instance you have: ^3√(x - 5)^3 = x - 5 and √(3x - 1) = 3x - 1 Well, by the square root 'variable' is... [^3√](x - 5)^3 = x - 5 and [√](3x - 1) = 3x - 1 That means you have '3' and '2', simply multiply it across like the exponents they are, this should give you: (x - 5)^3 = (x - 5)^3 and (3x - 1) = (3x - 1)^2 So, now divide like you would to get: x - 5 = x - 5 and 3x - 1 = 3x - 1 In conclusion, we would add the variables together. 2x = 10 and 6x = 2 Now divide. x = ? and x = ? I'm not sure if this is the right way to do this or not, but... it's one possible solution. I already checked the answers, so they're not wrong. Well, I hope this helps in someway! Have a great day! {---Ghostgate---}

OpenStudy (anonymous):

The answer to these type of questions should be x>=#, x<= # or all real numbers....

OpenStudy (alexrobin13):

|dw:1446596966448:dw| For the first, we simplify the exponents, using the multiplication rule (since they are separated by brackets.)

OpenStudy (alexrobin13):

We would do the same for 17, which is also true, since 2 x (1/2)=1!

OpenStudy (ghostgate):

I would go with alex's answer, he seems like he knows what he's doing.

OpenStudy (anonymous):

|dw:1446597258838:dw| I guess the threes cancel out and it will also be x-5?

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