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Mathematics
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use linear approximation to estimate cos(61 degrees)
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So we need to approximate \[\cos(\frac{61 \cdot \pi}{180}) \\ \text{ we know } \cos(\frac{60 \pi}{180})=\cos(\frac{\pi}{3})=\frac{1}{2} \text{ so find the tangent line to } \\ f(x)=\cos(x) \text{ at } x=\frac{\pi}{3}\]
so the answer is \[\frac{ 1 }{ 2 }+\frac{ \sqrt{3} }{ 2 }(\pi/180)\]
or \[\frac{ 1 }{ 2 }+\frac{ \pi \sqrt{3} }{ 360 }\]
I think you should have that -sin(pi/3) is -sqrt(3)/2 and not sqrt(3)/2
oh ok, that makes sense
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Thanks for the help!
np
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