Question

Gi

Answer 1

@freckles @imqwerty @Nnesha

Answer 2

@pooja195

Answer 3

@triciaal

Answer 4

if (x+p) is a factor of a polynomial f(x) then that means when f is divided by (x+p) the remainder is 0
\[\frac{f(x)}{x+p}=Q(x)+\frac{R}{x+p} \\ R=0 \text{ since we know } (x+p) \text{ is a factor of } f \\ \frac{f(x)}{x+p}=Q(x)+\frac{0}{x+p} \\ \frac{f(x)}{x+p}=Q(x) \\ f(x)=Q(x)(x+p) \\ \text{ what happens when you enter in } -p ?\]

Answer 5

-p in place of x?*

Answer 6

im not sure how to do that but for some reason i got f(-5)=0

Answer 7

replacing x with -p looks like this
f(-p)=Q(-p)(-p+p)
do you know what -p+p equals?

Answer 8

they cancel out?

Answer 9

-p+p is 0
so yes you have f(-p)=Q(-p)*0
anything times 0 is 0
so you have f(-p)=0

Answer 10

so you are right f(-5)=0

Answer 11

ah, thank you!

Answer 12

np

Answer 13

could you check one more of mine?

Answer 14

k

Answer 15

I am pretty sure it is B

Answer 16

f(x)=x^3 is odd degree and it looks like
horrible drawing but the thing is you should notice about this odd degreed polynomial you have opposite end behavior (not same)

Answer 17

if f(x)=-x^3 then you have the graph looks like this: