given the function f(x)=4(2)^x, section A is from x=1 to x=2 and section B is from x=3 to x=4 Part A: Find the Average Rate of change of each section Part B: How many times greater is the average rate of change of section B than section A? Explain Why one rate of change is greater than the other.
@AlexandervonHumboldt2
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@ganeshie8 can you help this person plz im not sure how to explane or do this problem right?
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can anyone help?
@dr0zier99
@ConnexusStudent0912
are you trying to evaluate it
Substitute the value of the variable into the equation and simplify f(3)=64
section a: f(x)=4(2)^x 1.......8 2.......16 section b: 3.......32 4.......64
section b is 4 times greater than section a
if i simplify f(3)=64 I get 0
I think that the definition of average rate \(r\) of change, can be this: \[\Large r = \frac{{f\left( {{x_2}} \right) - f\left( {{x_1}} \right)}}{{{x_2} - {x_1}}}\] where: \[\Large f\left( x \right) = 4 \cdot {2^x}\]
Michele _Laino is that for Part A?
it is for parts A, and B for example, for part A, we can write: \(x_1=1,\,x_2=2\)
oh ok
whereas for part B, we can use the same formula, with \(x_1=3,\,x_2=4\)
so i was correct when i said that part b was 4 times greater than part a
what about the last part for part b explain why one rate of change is greater than the other?
Yes you were correct when you said that
Thanks for helping guys but I don't know who to give the medal to
no problem
please give it to @dr0zier99 he/she worked more than me :)
ima boy
XD
ok! he worked more than me!
still i give medel to u cause u still helped
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