Use the trigonometric subtraction formula for sine to verify this identity sin(pi/2-x)=cosx First of all what is the trigonometric subrtraction formula? Second of all, how is this solved?
subtraction formula for sine: sin(A-B)=sin A cos B - cos A sin B so A=pi/2 and B=x in this case...
Okay so the left side then changes to sin pi/2 cos x - cos pi/2 sin x? So the whole equation is then sin pi/2 cos x - cos pi/2 sin x=cos x
u got it...good job! :)
but now what?
you did a great job. you got the final answer.
thats all? really
subrtraction formula>> sin(A-B)=sin A cos B - cos A sin B sin(pi/2-x) = sin pi/2 cos x - cos pi/2 sin x as cos pi/2 = 0 and sin pi/2 = 1 expression becomes, sin(pi/2-x) = (1)*cos x - 0*sin x
yes @cutiecomittee123 wat else u expecting? :P
Well then if thats it can either of you help me with another one?
and you have already done all that.
or a few other ones lol
how many r there?
i will let @princeharryyy help u :) good luck @cutiecomittee123
thanks man @superdavesuper
u gave her the solution.
Okay derive the trigonometric addition formula for sine sin(a+b)=sinacosb+cosasinb
there are a few maybe 3 questions besides the one I just asked
are you sure that you have to derive it, coz it's lengthy.
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