Use the trigonometric subtraction formula for sine to verify this identity
sin(pi/2-x)=cosx
First of all what is the trigonometric subrtraction formula?
Second of all, how is this solved?
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OpenStudy (superdavesuper):
subtraction formula for sine:
sin(A-B)=sin A cos B - cos A sin B
so A=pi/2 and B=x in this case...
OpenStudy (cutiecomittee123):
Okay so the left side then changes to sin pi/2 cos x - cos pi/2 sin x?
So the whole equation is then sin pi/2 cos x - cos pi/2 sin x=cos x
OpenStudy (superdavesuper):
u got it...good job! :)
OpenStudy (cutiecomittee123):
but now what?
OpenStudy (princeharryyy):
you did a great job. you got the final answer.
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OpenStudy (cutiecomittee123):
thats all? really
OpenStudy (princeharryyy):
subrtraction formula>> sin(A-B)=sin A cos B - cos A sin B
sin(pi/2-x) = sin pi/2 cos x - cos pi/2 sin x
as cos pi/2 = 0 and sin pi/2 = 1
expression becomes,
sin(pi/2-x) = (1)*cos x - 0*sin x
OpenStudy (superdavesuper):
yes @cutiecomittee123 wat else u expecting? :P
OpenStudy (cutiecomittee123):
Well then if thats it can either of you help me with another one?
OpenStudy (princeharryyy):
and you have already done all that.
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OpenStudy (cutiecomittee123):
or a few other ones lol
OpenStudy (princeharryyy):
how many r there?
OpenStudy (superdavesuper):
i will let @princeharryyy help u :) good luck @cutiecomittee123
OpenStudy (princeharryyy):
thanks man @superdavesuper
OpenStudy (princeharryyy):
u gave her the solution.
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OpenStudy (cutiecomittee123):
Okay derive the trigonometric addition formula for sine
sin(a+b)=sinacosb+cosasinb
OpenStudy (cutiecomittee123):
there are a few maybe 3 questions besides the one I just asked
OpenStudy (princeharryyy):
are you sure that you have to derive it, coz it's lengthy.