Question

You have two cards with a sum of (-12) in your hand.
A. What two cards do you have?
B. You add two more cards in your hand, but the total of the cards remains the same, (-12). Give some different examples of two cards you could choose.

Answer 1

I think the answer for A is 6 going 12 units to the left

Answer 2

You see this is a bit complicated because the first two could be any numbers really.. Such as -6 + (-6). If you're adding two more cards to the two that you already have, then both of the new ones would either have to be 0, or you'd have completely different numbers such as -10 + 6 + (-4) + (-4) ..

Answer 3

Is that what the question was asking for or was I just making stuff up here? XD

Answer 4

No thats what the questions asking for

Answer 5

1. You have two cards with a sum of -12 in your hand. What two cards could you have?

Examples:
-12 & 0
-11 & -1
-10 & -2
-9 & -3
-8 & -4
-7 & -5
-6 & -6
-14 & 2
-22 & 10

2. If I add two more cards to my hand, but the total sum of the cards remains the same then I must have added two cards that have a total sum of zero. I know that the sum of any number and its additive inverse is equal to zero so I must have a number and its additive inverse.

Examples:
-10 & 10
-2 & 2
-25 & 25
-99 & 99

Answer 6

@deadly_roses thank you for clarifying and expanding what I was trying to say. I felt like mine was a bit confusing. XD

Answer 7

lol no problem, yours was awesome btw ^_^ @xMissAlyCatx