The function f is continuous on the interval [2, 10] with some of its values given in the table below. Use a trapezoidal approximation with 4 trapezoids to approximate the integral from 2 to 10 of f of x dx.
@jim_thompson5910 Only person who seems to know calc
how far did you get?
Just started the problem.
I'm currently graphing online
Just decided that my graphing calculator would be a more efficient solution.
I agree. So you are able to plot the points and calculate the area of each trapezoid?
Plotted the points, kind of stuck on the trapezoid part.
What trapezoids are they referring to?
does this graph help at all (see attached) ?
here's a bigger version
Yes, the first one seems to be a triangle though
well if one parallel side of a trapezoid is 0, then we have a triangle
so you can either use the triangle area formula or the trapezoid area formula (with one base being 0)
Got 2.4 for the first one.
4.7 for the second one.
incorrect
Seriously?
yes
Damn calculator failed me, now I have to manually solve
maybe you typed in the wrong thing? post what you typed in so I can see
I went to STAT and put in the table above X under L1 and Y under L2
I then went to STAT CALC and calculated a quadratic formula almost equal to the points in stat.
why not just compute the area of each trapezoid using A = h*(b1+b2)/2
refer to my image attachment http://assets.openstudy.com/updates/attachments/563abfcfe4b031eb5b29ec94-jim_thompson5910-1446692170541-graph3.png
Thought I could use a shortcut.
Which failed. So I'll do that now.
First 2*4*1/2 = 4 Second 3*(3+8)/2 = 33/2 Third 2*(8+15)/2 = 23 Fourth (15+17)/2 = 16
Total 59.5
Right?
`First 2*4*1/2 = 4` .... disagree; you have the wrong numbers `Second 3*(3+8)/2 = 33/2` agree `Third 2*(8+15)/2 = 23` agree `Fourth (15+17)/2 = 16` disagree; should be 15 and 18 (not 15 and 17)
First 2*3*1/3= 3 Fourth (15+18)/2= 33/2
Final is 59.
`First 2*3*1/3= 3` agree `Fourth (15+18)/2= 33/2` agree `Final is 59.` agree
I have a similar one but it asks me to find f'(9) should I make a new post?
And as always, thanks.
`should I make a new post?` yes please
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