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Mathematics 25 Online
OpenStudy (hhopke):

WILL MEDAL AND FAN! Which of the following are true about solving radical equations algebraically? (listed below b/c I couldn't fit it all in this first box)

OpenStudy (hhopke):

-Isolate the radical part of the equation on one side and anything else on the other -Raise both sides of the equation to a power that will undo the radical (2 for a square root, 3 for a cube root, etc.) -If you check your answer by graphing both sides of the radical equation and your graphs don't cross, there is no intersection and no solution to the equation -If there are radicals on both sides of the equation, the problem must be solved graphically -When squaring both sides, it is possible that the equation will turn into a quadratic and will have two possible answers -Sometimes you will have radicals on both sides; that is okay

OpenStudy (hhopke):

you there, @Directrix?

Directrix (directrix):

Yes. I'm here thinking about this problem.

Directrix (directrix):

Have you found any statements yet that you think are true?

OpenStudy (hhopke):

Well, I know that the second one (raising powers) is true b/c we did it in class today, and...

OpenStudy (hhopke):

I'm pretty sure the first one (Isolation) is right but I'm not positive.

OpenStudy (hhopke):

I know that the third one (checking answers) is right, but the question asks for truths about solving algebraically (the online thing is picky- it's like one of those weird riddles).

Directrix (directrix):

I agree with these two so far: -Isolate the radical part of the equation on one side and anything else on the other -Raise both sides of the equation to a power that will undo the radical (2 for a square root, 3 for a cube root, etc.)

OpenStudy (hhopke):

And I'm not sure about the last three.

Directrix (directrix):

This is true. I just read a discussion about this on a website. I had never thought of checking solution this way. Add this to the true list: -If you check your answer by graphing both sides of the radical equation and your graphs don't cross, there is no intersection and no solution to the equation

Directrix (directrix):

This has to be false: -If there are radicals on both sides of the equation, the problem must be solved graphically That type radical equation can be done algebraically.

Directrix (directrix):

This seems true to me: -When squaring both sides, it is possible that the equation will turn into a quadratic and will have two possible answers Try squaring both sides of this: |dw:1446699297080:dw|

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