Question

Simplify cosθ + cosθtan2θ.
1
cscθ
secθ
sin2θ

Answer 1

is it \[\tan^2 \theta ~?\]

Answer 2

\[ \huge\rm \cosθ + \cosθ\tan^2θ\] like this ?

Answer 3

yes thats right

Answer 4

alright rewrite tan^2 in terms of cos and sin
tan= ??

Answer 5

what do u mean im a little confused

Answer 6

http://www.analyzemath.com/trigonometry/trigonometric_formulas.html
bookmark this link you really need this for trig

Answer 7

i was asking what's the reciprocal of tan ?

Answer 8

adj / opp

Answer 9

yes that's correct

Answer 10

that's the relation between trig functions
sin, cos , tan and csc ,sec ,cot are reciprocal of each other
tan x=sinx over cosx

Answer 11

ok

Answer 12

\[ \huge\rm \cosθ + \cosθ\color{ReD}{tan^2θ}\]
we need to rewrite tan^2 in terims of sin cos
\[\tan^2 \theta = \frac{\sin^2 \theta}{\cos^2 \theta}\]

Answer 13

ok i got that now so wat do ido next

Answer 14

replace tan^2 with sin^2/cos^2 and then simplify \[ \huge\rm \cosθ + \cosθ*\color{ReD}{\frac{sin^2 \theta }{cos^2 \theta }}\]

Answer 15

cos^2 is same as cos times cos

Answer 16

but how would i simplify it

Answer 17

\[ \huge\rm \cosθ + \cosθ*\color{ReD}{\frac{sin^2 \theta }{cos^2 \theta }}\]
\[\cos \theta + \frac{\cos \theta *\sin^2 \theta}{\cos \theta *\cos \theta}\]
cos^2 can be written as cos times cos
now canyou cancel out anything ?

Answer 18

oh ok so its the sin

Answer 19

sin ??

Answer 20

what do you mean ?