Question

Medal
for a velocity of 50 m/s at an angle of 40 degrees to the horizontal. how far above the release point does the ball hit the wall

Answer 1

How far away is the wall?

Answer 2

Yes Mr.Hamza, please provide all the information given.

Answer 3

ok

Answer 4

i did

Answer 5

wait a second

Answer 6

just focus on the picture

Answer 7

d=22.0 m
angle is 40.0

Answer 8

my question and the picture question is different

Answer 9

So you need to figure the time it takes to hit the wall so you can figure out the height at which it hits it. To do this, we need to know how fast our projectile is travelling in the x direction. This is give by our basic right triangle trig. We have
\[v_x=vcos(\theta)=50cos(40)\]
Since we need the x velcoity and we know the distance in the x direction is 22.0 meters. How long does it take to travel this distance? Well we divide distance by distance per second so we have
\[t=22/50cos(40)\]
And so the time it takes to hit the wall is found. From here we just need to find a function that gives us the y position. Can you take it from here?

Answer 10

so .34