Question

Quick question regarding Logs. Last one tonight I promise!
I have to decide which of the 2 are correct. I believe it to be the first one, but I am unsure. Just to have someone reassure me would mean a lot!!
My two choices are
logM^p=p x logM
or
(logM)^p= p x logM
Logarithm power rule

logb(x y) = y × logb(x)
this is the rule I am going by.

Answer 1

power rule \[\large\rm log_b x^y = y \log_b x\]

Answer 2

what's ur question ??

Answer 3

Which of the following statements are true? <---

Answer 4

ohh i see
so that's the power rule ive posted above
which can be written as \[\large\rm log_b (x)^y = y \log_b x\]

Answer 5

My one choice I have selected as being true is logM + logN = log(MN)

Answer 6

that's correct and that's the product rule!

Answer 7

I figured that was the rule they were looking for. Wouldn't that make it logM^p=p x logM.

Answer 8

I know either of the two logs I posted is true, I just don't know which one it is. :P

Answer 9

by this `x` do you mean multiplication sign or x variable ?
just making sure

Answer 10

multiplication. My bad

Answer 11

good that's the correct `power rule `

Answer 12

Okay. For the second one I posted (logM)^p= p x logM, what makes it different?

Answer 13

\[\huge\rm log~ m^\color{Red}{p} = \color{red}{p}* log~m\]

Answer 14

i don't see any difference
let say p =2 and m =3\[\log (3)^2 = (\log(3))^2\]

Answer 15

It's just the use of parentheses that changes that?

Answer 16

Is it basically like a trick to make you think it's not a choice?

Answer 17

well its gonna move to the front anyway
i mean we have to apply the power rule \[\rm (\log m)^p = p \log m\]

Answer 18

if I am reading it right yes the first one is correct by power rule

the difference that I see is the log of the number then to the power or the log of of the number raised to the power

Answer 19

logb(x y) = y × logb(x)
this is not correct \[\rm y *\log_b (x) = \log (x*y)\]

Answer 20

\[\log_b x+\log_b y = \log(x*y)\]