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Mathematics 7 Online
OpenStudy (anonymous):

QUICK help for medal?

OpenStudy (anonymous):

A manufacturer has been selling 1000 television sets a week at $450 each. A market survey indicates that for each $10 rebate offered to the buyer, the number of sets sold will increase by 100 per week. I know the demand function is y= 10x +1000 y=number of tvs sold x=the amount of rebate What I need to know is...How large a rebate should the company offer the buyer in order to maximize its revenue?

OpenStudy (anonymous):

I've looked all over the place, but no one can give a clear answer

OpenStudy (anonymous):

I'd appreciate it

OpenStudy (anonymous):

we can do this give me a second

OpenStudy (anonymous):

we are going to have to find the vertex of a quadratic equation

OpenStudy (anonymous):

i have no idea what a "demand" function is, but lets work slow if there is no rebate he sells 1000 at 450 for a total of 450000 if he gives one rebate of $10 he sells \(1000+100\) tvs at \(450-100\) each for a total of \[(1000+10)(450-10)\]

OpenStudy (anonymous):

if he gives two rebates he sells \(1000+200\) tvs for \(450-2\times 10\) for a total of \((1000+100\times 2)(450-10\times 2)\)

OpenStudy (anonymous):

and more generally if he gives \(x\) rebates he sells \[1000+100x\] tvs for \[450-10x\] dollars for a total of \[(1000+100x)(450-10x)\] dollars

OpenStudy (anonymous):

expand, get a quadratic with negative leading coefficient that opens down, find the vertex which will give you the optimal number of rebates as \(x\) and the amount made as \*y\)

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