Question

Check my answers: I"ll medal

Answer 1

yes you are correct!!!!!!!!!! good job!

Answer 2

AMAZING WORK!!!

Answer 3

@pitamar

Answer 4

dude awsome work

Answer 5

I think you just saying that so I"ll give you a medal

Answer 6

no im not

Answer 7

im being completely honest

Answer 8

@Michele_Laino

Answer 9

answer 3) is correct!

Answer 10

question #2
why you selected option 1?

Answer 11

michele nice catch on #2 didnt see that

Answer 12

that what i thought the answer was

Answer 13

question #1
we have to apply the formulas to your data, so I'm not able to say if your answer is correct!
Nevertheless, if you have applied such formulas, I think that your answer is correct!

Answer 14

question #4
the answer is correct!

Answer 15

question #5
I think that your answer is correct, since we can write this:
\(\Large y=A \cdot B^x\)
so, if we take the logarithm of both sides, we get:
\(\Large \log y=\log A+x \log B\)

Answer 16

so the only wrong one is #2 you think

Answer 17

yes!

Answer 18

sincerely, I don't know, please write the steps you used

Answer 19

please correct me, if I'm wrong:
if \(x\) is transformed into \(x^2\), then we have:
\((1,5),(9,16),(25,35),(49,67),(81,110)\)

Answer 20

ok so this: The wording of this problem is problematic (which of course is not the fault of the student). When I saw the word "linear," I attempted to find the coefficients a and b for the linear function y = ax + b that would fit the data. (In other words, if I were to take the first data point, (1,5), and substitute x=1 and y=5 into y =ax+b, the equation would have to be true, as it would for each and every one of the other data points.)

That failed.

So, I decided to use a quadratic (instead of linear) model: y = ax^2 + bx + c.
Substituting the first point, (1,5), results in 5 = a*1^2 + b*1 + c.
Substituting two more points, one at a time, results in two additional LINEAR equations.

These three linear equations can be solved simultaneously to obtain values for a, b and c.

I ended up with a = 1, b = 3/2, and c = 5/2.

Try substituting these three coefficients into the general form y=a*x^2 + bx + c and verifying for yourself that substitution of any or all of the given points results in an equation that is true.

Answer 21

ok! Nevertheless we have a \(quadratic\; law\) between \(x\) and \(y\) and not linear

Answer 22

we can write this formula:
\[\Large y = {\left( {x + \frac{3}{4}} \right)^2} + \frac{{31}}{{16}}\]

Answer 23

so I think you are correct!! Nevertheless we have to make a traslation first, namely:
\[\Large x \to x + \frac{3}{4}\]

Answer 24

then im wrong on only two: and two is C you think