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Mathematics 12 Online
OpenStudy (studygurl14):

PLEASE HELP! @Hero @ganeshie8 @amistre64

OpenStudy (studygurl14):

I already found teh critical points, but now I don't know what to do

OpenStudy (tkhunny):

Seems you should find a couple of derivatives. Go!

OpenStudy (studygurl14):

?

OpenStudy (tkhunny):

Analytical methods to find extreme values. Sounds like derivatives to me.

OpenStudy (studygurl14):

Yes, I know. Can you help?

OpenStudy (tkhunny):

Sure. What's the 1st derivative? If you don't like sec(x), try 1/cos(x).

OpenStudy (studygurl14):

the first derivative is secx tanx

OpenStudy (studygurl14):

But anyway, I already found critical points at (0,1) and (pi/ -1) What do I do after that?

OpenStudy (studygurl14):

EDIT: (pi, - 1)

OpenStudy (studygurl14):

uh @tkhunny ?

OpenStudy (studygurl14):

@freckles @amistre64

OpenStudy (tkhunny):

What are those critical points? Minimum? Maximum? Global? Local? None of the above?

OpenStudy (tkhunny):

It is hoped that we know up front that the secant blows up at \(\pi/2\).

OpenStudy (tkhunny):

Shall we do the 2nd derivative or are we done?

OpenStudy (studygurl14):

That's what I don't know how to find out. (min, max, global, local, etc.)

OpenStudy (zzr0ck3r):

suppose a and b are critical points with a<b Then if you look at c<a<d<b and c,d are both greater than a then a is a min, if they are both less than a, then a is a max. If one is greater and the other is less than, then it is neither. Or take the 2nd derivative and look at concavity

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