Question

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Answer 1

here, we have to compute number of moles of sodium azide. Such number is:
\[n = \frac{{39}}{{65}} = ...?\]
since the molecular weight of sodium azide is \(65\)

Answer 2

0.6

Answer 3

You find the # of moles of nitrogen and then since you know that it's STP, temperature = 298K and pressure is 1 atm.

so you would use the formula pV= nRT and solve for V

Answer 4

correct! we start with \(0.6\) moles of sodium azide.
Now, looking at the involved chemical reaction, we note that for every one mole of sodium azide, there are \(3/2\) moles of nitrogen. So the moles of produced nitrogen are:
\(0.6 \cdot (3/2)=...?\)

Answer 5

0.45

Answer 6

I got a different result, please retry

Answer 7

0.9

Answer 8

correct!

Answer 9

now, in order to get the requested volume, we can apply the procedure suggested by @Photon336

Answer 10

how would we do that

Answer 11

we can also apply this procedure:
since one mole occupies \(22.4\) liters, then \(0.9\) moles will occupy:
\(V=0.9 \cdot 22.4=...?\)

Answer 12

20.16

Answer 13

that's right!

Answer 14

so, what is the right option?

Answer 15

C

Answer 16

correct!

Answer 17

going to open up a new question

Answer 18

ok!