Question

if x≠0, then u/x+ 5u/x-u/5x=
A. 7x/5u
B. 5u/7x
C. 29u/5x
D. 31u/5x

Answer 1

It's fractions. Add them?

Get the denominators the same and add the numerators.

Answer 2

so is 7 x for the denominators? what about the u? they look too spreadeed out

Answer 3

i belive it is c

Answer 4

why is it c?

Answer 5

how did it became like 29 u if there is only like 9 u

Answer 6

Is it this? \(\dfrac{u}{x}+ \dfrac{5u}{x}-\dfrac{u}{5x}\)

Find a common denominator. We're just adding fractions.

Answer 7

So if we are just adding it wouldnt be 7u/7x?

Answer 8

Okay everything here is good :)

Answer 9

??

\(\dfrac{u}{x} + \dfrac{5u}{x} - \dfrac{u}{5x}\)

Common Denominator

\(\dfrac{5u}{5x} + \dfrac{25u}{5x} - \dfrac{u}{5x}\)

Add

\(\dfrac{5u + 25u - u}{5x} = \dfrac{29u}{5x}\)

Now, how are you feeling about anything that uses the number 7?

Answer 10

where did the 25 appear from?

Answer 11

Its c.

Answer 12

I still dont understand

Answer 13

the lowest common multiple of x,x and 5x is 5x
so you can do this by making the denominators in the 3 fractions the same

for the first fraction u/x you multiply the u and the x by 5 giving

5u/5x

Answer 14

do you follow that?

Answer 15

@Kfsv10 have you found a solution?

Answer 16

So it could become in any number?

Answer 17

yes. It is just solving fractions. for example x(1/3 + 2/3) is same as x/3 + 2x/3.

so u/x+ 5u/x-u/5x = u/x(1/1 + 5/1 - 1/5) = u/x(29/5)

which is 29u/5x

Answer 18

you need to convert 5u/x to a fraction with 5x as the denominator in the same way as above . The last fraction is u/5x has a denominator of 5x already.