The price of bronze has increased by 10% per year from 2000. In the year 2000, Harry bought a bronze medal for $120. Which of the following functions f(x) can be used to represent the price of the medal x years after 2000? f(x) = 120(0.9)x f(x) = 10(120)x f(x) = 120(1.1)x f(x) = 10(1.1)x
Hi @oscar5652551 , Do you know how to deal with percents and such? Such as when to apply them to certain amounts, especially over the course of year(s) or any length of time?
Also, are the 'x' components of your function being multiplied by the entire function, or, is it an exponent?
nope haha
exponent
Alright, goody good. I can help you. I will not give you the direct answer, but it's pretty simple and I am sure you will get it :-)
\[A=P(1+r)^{t}\]
A= new amount ; P= Starting amount ; r= rate ; t = time
The price of bronze has increased by 10% per year from 2000. In the year 2000, Harry bought a bronze medal for $120. Which of the following functions f(x) can be used to represent the price of the medal x years after 2000? t = x r = .10 (10%) P= $120, simply 120. A= TBD.
Plug these into the function I listed above to tell me what you get.
a=120(1+.10)^t
Excellent! Now, add what is inside your parenthesis.
1.1
Bravo. So, what does that make your entire equation?
a=120(1.1)^t
\[A=120(1.1)^{t}\]
Well done. :-)
thx so much :)
You're welcome! If you need more help, mention me. I am always up to helping.
ok i will thx
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