Question

WILL FAN AND MEDAL!!

Answer 1

You know that:

\(\huge\color{magenta}{ \ell }\)
\(\normalsize\color{ slate }{\Huge{\bbox[5pt, lightcyan ,border:2px solid black ]{ \color{lightcyan}{\Huge\frac{~~~~~~~~\frac{~}{~~~\frac{~\frac{}{}~}{~\frac{~}{~}}~~~~}~~~}{~\frac{\frac{~}{~\frac{~\frac{}{~}}{~}}~~}{~}~~} } }}}\) \(\huge\color{darkviolet}{ w }\)

\(\huge\color{blue}{ {\rm A} = \color{magenta}{ \ell }\times{\color{darkviolet}{ w }} }\)

Answer 2

would it then be A?

Answer 3

Now, your side \(\ell\) and \(w\) are?
(I can't see the attachment clearly)

Answer 4

the one on the side is 2h-1 and the one on the bottom is 3h+5

Answer 5

Yes, so:

\(\large\color{black}{ {\rm A}=\ell \times w }\)
\(\large\color{black}{ {\rm A}=\left(2h-1\right) \times \left(3h+5\right) }\)

Answer 6

So you have to multiply:

Answer 7

A?

Answer 8

I doubt that:

Answer 9

\(\large\color{black}{ \displaystyle (a+b)\times (c+d) = \\[0.7em] (a\times c)+(a\times d)+(b\times c)+(b\times d) }\)

Answer 10

you can use that \(\LARGE \color{black}{\Uparrow}\)

Answer 11

oh its 6h2+7h−5

Answer 12

Yes, very good!
\(6h^2+7h-5\) is correct!

Answer 13

awesome thank you!!!

Answer 14

Anytime!