Circle a and circle b are congruent cd is a chord of both circles. id cd= 16 cm and the radius is 17 cm how long is ab
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OpenStudy (anonymous):
OpenStudy (aaronandyson):
Options?
OpenStudy (aaronandyson):
@TangerineSkyys
OpenStudy (campbell_st):
the line from the centre to the chord is a perpendicular bisector of the chord...
so half cd is 8
use pythagoras' theorem to find the length from A to the chord
\[AC^2 = 17^2 - 8^2\]
then double the answer since the circles are congruent
hope it helps
OpenStudy (campbell_st):
oops... let E be the intersection of cd and AB
I ment to say
\[AE^2 = 17^2 - 8^2\]
then double the answer
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OpenStudy (mathstudent55):
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Directrix (directrix):
17^2 = 8^2 + x^2
289 = 64 + x^2
Subtract 64 from both sides
Find square root of result.
Double the value of x to get the length of AB.
@TangerineSkyys
OpenStudy (anonymous):
so would the answer be 30?
OpenStudy (anonymous):
@Directrix
Directrix (directrix):
>so would the answer be 30?
Correct.
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