Question

http://icecream.me/7f8680e342b20f2e81460c7b94770674

Answer 1

Sorry, idk how to do that.

Answer 2

That's fine, you tried to understand it. :)

Answer 3

@Directrix ?

Answer 4

The "Wolf" says see the attachment.

I am still working on the problem.

Answer 5

What do you mean by "the wolf says"? lol
Alright.

Answer 6

Wolframalpha.com, affectionately known as "The Wolf."

Answer 7

Oh? I didn't know that. Thanks for the trivia. =)

Answer 8

http://www.wolframalpha.com/input/?i=cos%28sin%5E-1%281%2Fx%29%29+%3D

Answer 9

Wait, what?

Answer 10

brb I must take out laundry. Sorry

Answer 11

back

Answer 12

wb :)

Answer 13

thanks :)

Answer 14

hey pooja changed her pfp

Answer 15

pooja left this post

Answer 16

wait what?

Answer 17

pooja came back

Answer 18

um ok o_o

Answer 19

ok lets do the ques

Answer 20

0.0

Answer 21

okay...

Answer 22

u want direct answer or step wise :)

Answer 23

lol what ... I thought direct answers ware against the rules

Answer 24

no is not like that :)

Answer 25

were*

I just need hints, we'll only step by step if I really don't get it :p

Answer 26

only do* omg my grammar -_- lol

Answer 27

its ok

Answer 28

use this identity-
\[\cos(\sin^{-1} a)=\sqrt{1-a^2}\]

Answer 29

eh? o-o

Answer 30

sorry was trying to figure it out myself, somewhat xD

Answer 31

yes thats an identity u just need to figure out what is 'a' in your ques and put that in the result ->sqrt{1-a^2}

Answer 32

oh um, Directrix gave me this formula \[\sqrt{1-\frac{1}{x^{2}}}\]

Answer 33

yes correct

Answer 34

so I should solve in terms of or for* x? o-o

Answer 35

not sure which

Answer 36

>>yes thats an identity u just need to figure out what is 'a' in your ques and put

It seems to be that a would be 1/x.

Answer 37

my computer won't let me reply properly ...

Answer 38

maybe ur computer hates u ):

Answer 39

I got \[1-\frac{1}{x}\]and my mom is yelling at me to do housework

Answer 40

lol

Answer 41

ack, it's wrong x_x

Answer 42

that's the answer? o_o

Answer 43

yes B)

Answer 44

OH.

Answer 45

wait but wouldn't I be right too since I just simplified it

Answer 46

nope, says it's wrong
well it says x^2

Answer 47

oopsie i made a lil mistake :)

Answer 48

.-.

Answer 49

it will be this-\[\sqrt{1-\frac{ 1 }{ x^2 }}\]

Answer 50

I put that and got "wrong answer" too before lol

Answer 51

oh lawd what is happening

ok so we have this-
\[\cos(\sin^{-1} \frac{ 1 }{ x })\]
from here we get that a=1/x

now we have to express it in terms of x

and we know that
\[\cos(\sin^{-1} a)=\sqrt{1-a^2}\]
we put our a in it
\[\\[\cos(\sin^{-1} \frac{ 1 }{ x })=\sqrt{\frac{ x^2-1 }{ x}}\]=\sqrt{1-\frac{ 1 }{ x^2 }}\]
or u can also write it like this-\[\cos(\sin^{-1} \frac{ 1 }{ x })=\sqrt{\frac{ (x-1)(x+1) }{ x }}\]
or like this-\[\cos(\sin^{-1} \frac{ 1 }{ x })=\sqrt{\left( 1-\frac{ 1 }{ x } \right)\left( 1+\frac{ 1 }{x } \right)}\]

Answer 52

http://icecream.me/8c2c9abcd3bba3cff51faec8f7f6d26a

Answer 53

wut
I think there was some LaTex issues there haha

Answer 54

yeah ):
ok try this-
\[\sqrt{\frac{ x^2-1 }{ x }}\]

Answer 55

hey wait
it says assume x to be positive
maybe we have to do something with it

Answer 56

0-0

Answer 57

ah try this-
\[\pm \sqrt{1-\frac{ 1 }{ x^2 }}\]

Answer 58

that doesn't exist as an option, the symbol\[\pm\]

Answer 59

D:

Answer 60

lol

Answer 61

so I found this http://www.algebra.com/algebra/homework/Trigonometry-basics/Trigonometry-basics.faq.question.769293.html

Answer 62

csc is different from cos

Answer 63

I also found this http://openstudy.com/study#/updates/4de461654c0e8b0b0533aed8

Answer 64

):

Answer 65

theres definitely some prblm

Answer 66

according to link 1, the answer is cos(arcsin (1/x) )

Answer 67

did u use space when u typed your answer?

Answer 68

nope.

Answer 69

ok try this-\[\frac{ \sqrt{x^2-1} }{x }\]

Answer 70

I tried the arcsin thing, it wouldn't let me type arcsin

Answer 71

um I think I only have one attempt left

Answer 72

ok lets think

Answer 73

see the answer is definitely this

Answer 74

i think they want a simplified answer

Answer 75

i think \[\frac{ \sqrt{x^2-1} }{ x}\]shuld wrk

Answer 76

how about this problem instead? I have full attempts\[\sec{\left(cos^{-1}\frac{7}{x}\right)}\]

Answer 77

@imqwerty lol is that ok?

Answer 78

wait a min lol m on a phone call

Answer 79

ok xD

Answer 80

ok done :)

Answer 81

okay :]

Answer 82

x/7 for sure B)

Answer 83

\[\sec(\cos^{-1} \frac{ 7 }{ x })=\frac{ 1 }{ \cos \left( \cos^{-1} \frac{ 7 }{ x } \right) }\]\[=>\frac{ 1 }{ \frac{ 7 }{x} }=\frac{ x }{ 7 }\]

Answer 84

okay

Answer 85

(B

Answer 86

It's correct :o

Answer 87

ヽ༼ຈل͜ຈ༽ﾉ︵ ┻━┻

:D

Answer 88

I input/submitted the other one and it's correct too

Answer 89

┻━┻︵ヽ༼ຈل͜ຈ༽ﾉ︵ ┻━┻

Answer 90

so then this one ? lol \[\sin\left(\tan^{-1}x\right)\]

Answer 91

I looked at your solution for 7/x but it doesn't apply to this one lol

Answer 92

its this-
\[\frac{ x \sqrt{x^2+1} }{ x^2+1 }\]

Answer 93

what how 0.0

Answer 94

just use the identity-
\[\sin(\tan^{-1} a)=\frac{ a }{ \sqrt{a^2+1} }\]
note that i multiplied both numerator and denominator with sqrt{x^2 +1}
to remove the square root from the denominator

Answer 95

but i think that u shuld enter this as the answer-\[\frac{ x }{ \sqrt{x^2+1} }\]

Answer 96

oh okay

Answer 97

:)