Question

3

Answer 1

molality = moles of solute/kg of solvent
I dont know what are the options in your problem

0.75 moles of Isoamyl salicylate + 1 kg of ethyl alcohol

0.75 moles x 208.25 g/mol = 156.18 g Isoamyl salicylate

1000g ethyl alcohol x 0.7893 g/mL= 789.3 g ethyl alcohol

Answer 2

calculate the moles in 117.2 g of isoamyl salicylate,
then the g of Ethyl alcohol to prepate a 0.75 molal solution with the moles of isoamil salicylate
finally calculate the volume of the g of ethyl alcohol with the density

(117.2 g /208.25 g ) x (1000 g /0.75 mol ) x (1 mL /0.7893 g) = xx.xx mL Ethyl alcohol