Question

Find the inverse of the following function:

Answer 1

\[y=\log _{4}(2x-1)+3\]

Answer 2

Can you make an equation prior to x like y in your question

Answer 3

replace x by y and y by x and then write x in terms of y

Answer 4

So.... \[x=\log _{4}(2y-1)+3\]

Answer 5

so we have
\[x= \log_{4} (2y-1)+3 \]

Answer 6

then
\[(x-3)=\log_{4} (2y-1)\]

Answer 7

wow..sorry for the orientation. :D

Answer 8

then
\[4^{x-3}= 2y-1\]

Answer 9

@jango_IN_DTOWN you are correct. way to go!

Answer 10

then
\[y=(4^{x-3}+1)/2\]

Answer 11

f^-1(x) = (4^x-3+1)/2

Answer 12

now replace x by y and y by x again
and write x as
\[f ^-1 (x)\]

Answer 13

it will give the inverse function