The rectangular bird sanctuary with one side along a straight river is to be constructed so that it contains 8 km^2 of area. Find the dimensions of the rectangle to minimize the amount of fence necessary to enclose the remaining three sides.
you want to apply calculus for this. have you learned calculus before?
Yes Can you help me derive an equation
yes. You can take the advantage of calculus at this point. fist let's draw our sanctuary|dw:1447056819116:dw|d say it has x and y sides
Area(A) = xy = 8
sum of distance of fence(D) = 2x + y
now lets take D in terms of x using above 2 equations
D = 2x + 8/x
now this is the distance of fence. you need to find minimum of it. so we take first derivative of D with respect to x
ok
So d(D)/d(x) = 2 - 8/x^2
and you will get \[\frac{ d(D) }{ d(x) } = \frac{ 2(x-2)(x+2) }{ x^2 }\]
now draw the graph. |dw:1447057233381:dw|
I lost you for how you got your equation for d/x
how is it 2-(8/x^2)
if put values for x from negative to positive. you will notice that if x<-2 ; d(D)/d(x) is positive if x = -2 ;d(D)/d(x) is zero if -2 <x < 2 ;d(D)/d(x) is negative if x = 2 ;d(D)/d(x) is zero if x < 2 ;d(D)/d(x) positive
that's how I argue that fence has its minimum value when x = 2 and of course a distance cannot be an negative value anyway:). so we forget x = -2
now go back to our distance equation D = 2x + 8/x
put x = 2 D = 2*2 + 8/2 = 4 +4 = 8
hope this helps
thanks!
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