http://prntscr.com/90qeze
so we know that \(5b+1s+(7b+2s)=$51.69\) and we also know that \(b=$3.69\) \(5b+1s+(7b+2s)=$51.69\\12b+3s=$51.69\\12(3.69)+3s=51.69\\44.28+3s=51.69\\3s=7.41\\$2.47\)
so that's the final answer?
s=2.47, yeah
ok, and any idea about the second problem?
\(E=\color{red}{m}c^2\) we want to get m alone on one side, how do we do that? we hvae to get ride of what's attached to m by doing opposite operations here, the \(c^2\) is attached to m via multiplication. \(E=\color{red}{m}*c^2\) we divide both sides by \(c^2\) and we get \(E=\color{red}{m}c^2\\ \dfrac{E}{c^2}=\dfrac{\color{red}{m}c^2}{c^2} \\\dfrac{E}{c^2}=\dfrac{{m}\cancel{c^2}}{\cancel{c^2}} \\\dfrac{E}{c^2}=\color{red}{m}\)
ok ty i have two more questions..think you can help? cx
maybe
maybe isn't an answer..
yes it is. I just answered
maybe
-.-
I won't know if I can help until I see the questions. \(\huge \color{pink}\heartsuit\)
shhhhhhh -.-
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