20. When we have zero on the bottom of the slope, we call that no slope because of the rule that zero can never be in the denominator of a fraction. An example of this would be a line that goes through the points (2, -3) and (2, 4). If you plotted these points, what would this graph look like? What should this equation be? My Answer~ M=4+3/2-2 M=7/0 The slope is undefined The line would look like a vertical line. What my teacher said~ one more question here that needs to be answered. What is that question? @atrey6s3x6
@atreyu6s3x6
You are correct: 1) The sloe is undefined because it involves division by zero. 2) It is a vertical line. 3) You are missing the equation of the line.
You just need to supply 3) above.
Ok would you mind helping me find the equation?
you got this :)
\(\text {20. When we have zero on the bottom of the slope, we call that no slope}\) \(\text{ because of the rule that zero can never be in the denominator of a fraction.}\) \(\text { An example of this would be a line that goes through the points (2, -3) and}\) \(\text{ (2, 4). If you plotted these points, what would this graph look like?} \) \(\color{red}{ What ~should ~this ~equation ~be?} \)
Notice in that the two given points have x = 2, correct? No matter what the y-coordinate of any point is, x is always 2. In other words, there is no restriction on y. The only restriction is that every point has to satisfy the equation x = 2. That is exactly the equation, x = 2.
Similarly, for a horizontal line, the eqation is y = number
Give me a second, I'm trying to do the steps
ok @mathstudent55 if I show you the steps I did can you check it?
@atreyu6s3x6 can you check my steps?
sure post them :)
You already showed your slope calculation and showed it ends in division by zero. Then you wrote that the slope is undefined. A line with undefined slope is vertical. All you need to add to your work is The equation of the line is x = 2.
Points ~~ (2, -3) and (2, 4). (X1, y1) (x2,y2) (x2,y-3) (x2,y4) M= 4-2/-3-2 M= 2/-5 Y=mx+b this is how far i got...
he gave you the answer :) @abbycross167
oh thank you kindly! @mathstudent55
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