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What are the foci of the Ellipse? 36x^2+9y^2=324
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You can figure this out by writing the equation in ellipse form.
So you have to divide both sides by 324.
why 324? Because 324 divides evenly by both 9 and 36
afterwards your equation should look like this \[x^2/9 + y^2/36 =1\]
\[c^2=a^2-b^2\]
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But what are a and b?
a^2 is the number under y^2. b^2 is the number under x^2
So c=sqrt(36-9)
c=5. Because c=5, the foci are located at (0,5) and (0,-5)
http://www.mathwarehouse.com/ellipse/images/focus_equation_better.gif heres a picture if you still need help
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Okay Thankyou so much helped a lot!
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