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f(x)=(3x-3)e^-6x find the critical points
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\(\large\color{black}{ \displaystyle f(x)=(3x-3)e^{-6x} }\)
Did you find the derivative \(\large\color{black}{ \displaystyle f'(x) }\) ?
no
\(\large\color{black}{ \displaystyle \frac{ d }{dx}\left[ ~A(x)\times S(x)~\right]=A'(x)S(x)+A(x)S'(x) }\)
that is the product rule
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\(\color{black}{ \displaystyle \frac{ d }{dx}\left[ ~(3x-3)\times e^{-6x}~\right]=(3x-3)'\times e^{-6x}+(3x-3)\times (e^{-6x})' }\)
ok I got that
Ok, so the frst derivative f \('\)(x) is?
that is the derivative
(I want you to give me the equation of the derivative)
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\[3e ^{-6x}+(3x-3)e ^{-6x}\]
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