Question

Find an Equation for the Rational Function which has Zero at x=6, a hole at x=3, and asymptotes at x=4 and y=5

Halp pls <3

Answer 1

i got R(x) = [(x-3)(x-6)/(x-3)(x-5)(x-4)]
and i need to know how to graph it ;-; that's the biggest problem

Answer 2

@Nnesha @amistre64

Got an idea on how to grah this?

Answer 3

your function does not meet your conditions

Answer 4

asymptote at y=5, is a horizontal attribute, its a limit of leading coefficients

Answer 5

and you graph with technology, otherwise you sketch with enough identifiers to establish what you are trying to convey

Answer 6

So basically, my Function is wrong, and i couldnt graph it right because of that?

Answer 7

its almost right :) instead of (x-5) just multiply it by 5

this is assuming a y=5 asymptote is not a typo

Answer 8

it's an asymptote, so it's basically R(x) = [5(x-3)(x-6)/(x-3)(x-4)]

Answer 9

thats better

when the top and bottom functions are of the same degree, the y asymptote is determined by the leading coefficients: 5/1= 5

Answer 10

y = 5(x-3)(x-6)/((x-3)(x-4))

Answer 11

youll have to indicate a hole at x=3, but other than that it looks pretty much like that

Answer 12

how can i indicate a hole at x=3 if it doesnt pass through x=3?

Answer 13

you draw a hole there to indicate that there is no value there

Answer 14

Ah, i see. Was a bit confused, but htat makes sense.