Question

ALGEBRA HELP
(f•g)(1) and (g•f)(-1)

Answer 1

@jim_thompson5910 help please

Answer 2

Hey! idk why that got deleted! lol

\[\large (f\cdot g)(1) \rightarrow f(g(1))\]

Answer 3

Is it \[\Large (f \cdot g)(1)\] or is it \[\Large (f \circ g)(1)\]??

Answer 4

theres two questions for the graph the first one is (f•g)(1) the second question is (g•f)(-1)

Answer 5

If it is \[\Large (f \cdot g)(1)\] then
\[\Large (f \cdot g)(1) = f(1) \cdot g(1)\]

Answer 6

Ok I'm writing this in my notebook

Answer 7

to find the value of f(1), you look at the y coordinate of the point on f(x) when x = 1
to find the value of g(1), you look at the y coordinate of the point on g(x) when x = 1

Answer 8

yes . I look and I see that g(x) y coordinate is -5 am I right ?

Answer 9

yes (1,-5) is a point on g(x)

Answer 10

wow :) yay and for f(x) is 3

Answer 11

yes

Answer 12

:D Yay . so how do I right this in the function ?

Answer 13

is that the answer ?

Answer 14

no

Answer 15

to find the value of f(1), you look at the y coordinate of the point on f(x) when x = 1
that y coordinate is 3, so f(1) = 3


to find the value of g(1), you look at the y coordinate of the point on g(x) when x = 1
that y coordinate is -5, so g(1) = -5

Answer 16

f(1) = 3
g(1) = -5

\[\Large (f \cdot g)(1) = f(1) \cdot g(1)\]
\[\Large (f \cdot g)(1) = 3 \cdot (-5)\]
\[\Large (f \cdot g)(1) = -15\]

Answer 17

I was just about to ask that lol . Thanks a lot Professor Jiim for helping me learn this :)

Answer 18

you're welcome

Answer 19

ok what about the second question the negative 1 I do the same exact thing