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Mathematics 19 Online
OpenStudy (aizhalee):

ALGEBRA HELP .Last question graph each function of g

OpenStudy (aizhalee):

g(x)=f(2x)

OpenStudy (just_one_last_goodbye):

So coordinating points of G correct?

OpenStudy (aizhalee):

thank you for stopping by to help me :)

OpenStudy (aizhalee):

yes

OpenStudy (just_one_last_goodbye):

No prob xD

OpenStudy (aizhalee):

thank you , so can you explain on how I can do that . Its a tad bit confusing

OpenStudy (just_one_last_goodbye):

are the coordinates already showing?

OpenStudy (just_one_last_goodbye):

aren't*

OpenStudy (aizhalee):

no using the graph that I posted up there to plug in . to solve the question

OpenStudy (just_one_last_goodbye):

@pooja195 please help my friend I dont understand the question

OpenStudy (aizhalee):

its ok . I dont understand it too well either ;/

OpenStudy (just_one_last_goodbye):

stupid school questions @pooja195

OpenStudy (just_one_last_goodbye):

@SolomonZelman bro please help my friend ^_^ you very smart of these kind of questions

OpenStudy (just_one_last_goodbye):

@tkhunny please help

OpenStudy (tkhunny):

Domain of f(x) is what?

OpenStudy (aizhalee):

-2, 2 @tkhunny

jimthompson5910 (jim_thompson5910):

from the graph, we see that f(2) = 2 because (2,2) is on the graph of f(x) if we plug x = 2 into g(x), we get g(x) = f(2x) g(2) = f(2*2) .... replace each x with 2 g(2) = f(4) g(2) = undefined why undefined? Because the graph of f(x) doesn't stretch to x = 4. So f(4) is not defined what happens when we plug in x = 1 into g(x) ?

OpenStudy (aizhalee):

Thanks a lot but if we plug in 1 . then 1*1= 1

OpenStudy (tkhunny):

So, "2x" has to be contained in [-2,2]. thus, Domain of g(x) is [-1,1]. So?

OpenStudy (aizhalee):

am I correct or did I do a mistake

OpenStudy (aizhalee):

alright I'll just add these into my notes

jimthompson5910 (jim_thompson5910):

plug x = 1 into g(x), to get g(x) = f(2x) g(1) = f(2*1) .... replace each x with 1 g(1) = f(2) g(1) = ???

OpenStudy (aizhalee):

defined

OpenStudy (aizhalee):

or undefined

jimthompson5910 (jim_thompson5910):

what is f(2) equal to?

OpenStudy (aizhalee):

g(1)

jimthompson5910 (jim_thompson5910):

look at the graph

OpenStudy (aizhalee):

2

jimthompson5910 (jim_thompson5910):

yes, so hopefully you see how g(1) = 2 ?

OpenStudy (aizhalee):

Yes I agree

jimthompson5910 (jim_thompson5910):

how about g(-1) ?

OpenStudy (aizhalee):

im guessing -2

jimthompson5910 (jim_thompson5910):

plug x = -1 into the g(x) function and use the f(x) graph

OpenStudy (aizhalee):

g(x) = f(2x) g(-1) = f(2*-1) .... replace each x with 1 g(-1) = f(-2) g(-1) = -2

jimthompson5910 (jim_thompson5910):

f(-2) is NOT equal to -2

jimthompson5910 (jim_thompson5910):

draw a vertical line through x = -2 on the graph you have where does this vertical line cross the f(x) graph? what is the y coordinate of this point?

OpenStudy (aizhalee):

4

OpenStudy (aizhalee):

if I do a vertical line there really isnt a y coordinate

OpenStudy (aizhalee):

i tried >.<

jimthompson5910 (jim_thompson5910):

you're looking at the graph where f(x) is a horizontal line through y = 2 right?

OpenStudy (aizhalee):

yes

jimthompson5910 (jim_thompson5910):

you should see that x = -2 corresponds to y = 2 on the graph so (-2,2) lies on f(x)

jimthompson5910 (jim_thompson5910):

agreed?

OpenStudy (aizhalee):

yes sir

jimthompson5910 (jim_thompson5910):

so hopefully you see how g(-1) = 2 as well?

OpenStudy (aizhalee):

yes

OpenStudy (aizhalee):

whats next

jimthompson5910 (jim_thompson5910):

so as @tkhunny is saying, the domain of f(x) is [-2,2] and the domain of g(x) shrinks to [-1,1] so thinks have shrunk horizontally by a factor of 2

jimthompson5910 (jim_thompson5910):

the graph of g(x) is simply a horizontal line through y = 2 but it is restricted on the interval \(\Large -1 \le x \le 1\)

OpenStudy (aizhalee):

thanks a lot im adding this in my notes

jimthompson5910 (jim_thompson5910):

np

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